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3x^2-105x-360=0
a = 3; b = -105; c = -360;
Δ = b2-4ac
Δ = -1052-4·3·(-360)
Δ = 15345
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{15345}=\sqrt{9*1705}=\sqrt{9}*\sqrt{1705}=3\sqrt{1705}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-105)-3\sqrt{1705}}{2*3}=\frac{105-3\sqrt{1705}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-105)+3\sqrt{1705}}{2*3}=\frac{105+3\sqrt{1705}}{6} $
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